• 个人简介

    打字、开灯游戏在最下方
    AC鸭,你%¥#!@@#¥%#¥@#!!@¥#%#@¥#¥%

    《代码决定人生》

    如果26个英文字母 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

    分别等于 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26

    那么

    Knowledge (知识): K+N+O+W+L+E+D+G+E= 11+14+15+23+12+5+4+7+5=96%。

    Workhard (努力工作):W+O+R+K+H+A+R+D= 23+15+18+11+8+1+18+4 =98%。

    也就是说知识和努力工作对我们人生的影响可以达到96%和98%。

    Luck(好运) L+U+C+K=12+21+3+11=47%。

    看来,这些我们通常认为重要的东西却并没起到最重要的作用。

    那么,什么可以决定我们100%的人生呢?

    是Money(金钱)吗?

    M+O+N+E+Y=13+15+14+5+25=72%。

    看来也不是。

    是Leadership (领导能力)吗?

    L+E+A+D+E+R+S+H+I+P=12+5+1+4+5+18+19+9+16=89%

    还不是。

    金钱,领导能力也不能完全决定我们的生活。那是什么呢?

    其实,真正能使我们生活圆满的东西就在我们的代码里面!

    IOSTREAM(输入输出流所在的头文件) =9+15+19+20+18+5+1+13=100%。

    LONG LONG D(定义一个long long类型的变量"d") (12+14+7+15)*2+4=100%

    劝你还是好好写代码吧。

    本人网站最高TOP1

    O(n)复杂度的“排序”

    #include<bits/stdc++.h>
    
    using namespace std;
    
    priority_queue<int> q;
    
    int main(){
    	int n;
    	cin >> n;
    	for(int i = 1; i <= n; i++){
    		int num;
    		cin >> num;
    		q.push(-num);
    	}
    	for(int i = 1; i <= n; i++){
    		cout << -q.top() << " ";
    		q.pop(); 
    	}
    	
    	return 0;
    }
    

    打字游戏:

    #include"stdio.h"
    #include"stdlib.h"
    #include"windows.h"
    #include"conio.h"
    #include<bits/stdc++.h>
    #include<climits>
    
    using namespace std;
    void kong(int num){
    	for(int i = 0; i < num; i++){
    		printf(" ");
    	}
    }
    void enter(int num){
    	int i;
    	for(i = 0; i < num; i++){
    		printf("\n");
    	}
    }
    int main(){
    	long long life; 
    	enter(15);
    	kong(10);
    	printf("请选择模式:a.入门, b.新手, c.中等, d.高手, e.大佬, f.递进, g.自定义");	
    	char xx;
    	xx = getch();
    	if(xx != 'g'){
    		life = 3;
    	}
    	kong(40);	
    	int shi;
    	if(xx == 'g'){
    		system("cls");
    		enter(15);
    		kong(40);
    		cout << "请输入时间隔(ms):";
    		cin >> shi;
    		kong(40);
    		cout << "请输入生命数:";
    		cin >> life;
    	}
    	system("cls");
    	char xuan = 'y';
    	int mxscore = 0;
    	int levels = 1;
    	int score = 0;
    	int num = 0;
    	int col = 0;
        while(xuan == 'y'){
        	int lines = 0;
        	mxscore = max(mxscore, score);
        	system("cls");
        	for(int i = 0; i < 15; i++) {
    			printf(" ");
    		}
    		if(xx == 'f'){
    			for(int i = 0; i < 5; i++) {
    				printf(" ");
    			}
    		}
    		printf("levels:%d", levels);
    		kong(5);
    		printf("score:%d", score);
    		kong(5);
    		printf("highscore:%d", mxscore);
    		kong(5);
    		printf("life:%d", life);
    		printf("\n");
    		kong(30);
    		printf("1---Pause");
    		kong(9);
    		printf("0---Exit");
    		printf("\n");
    		for(int i = 0; i < 80; i++){
    			printf("_");
    		}
    		enter(1);
    		srand(static_cast<unsigned int>(time(0)));
    		num = rand() % 26;
    		col = rand() % 80;
    		while(xuan == 'y'){
    			lines++;
    			if(lines > 25){
    				lines = 0;
    				life--;
    				break;
    			}
    			kong(col);
    			printf("%c", 'a' + num); 
    			if(xx == 'a'){
    				Sleep(200);
    			}else if(xx == 'b'){
    				Sleep(158);
    			}else if(xx == 'c'){
    				Sleep(100);
    			}else if(xx == 'd'){
    				Sleep(50);
    			}else if(xx == 'e'){
    				Sleep(25);
    			}else if(xx == 'f'){
    				if(score <= 50){
    					levels = 1;
    					Sleep(180);
    				}else if(score <= 200){
    					levels = 2;
    					Sleep(150);
    				}else if(score <= 500){
    					levels = 3;
    					Sleep(110);
    				}else if(score <= 1000){
    					levels = 4;
    					Sleep(70);
    				}else if(score <= 1750){
    					levels = 5;
    					Sleep(50);
    				}else{
    					levels = 6;
    					Sleep(30);
    				}
    			}else{
    				Sleep(shi);
    			}
    			
    			
    			printf("\b \n");
     
    			if(kbhit()){
    				char c = getch();
    				if(c == 'a' + num){
    					score += 10;
    					break;
    				}else if(c == '0'){
    					exit(0);
    				}else if(c == '1'){
    					c = getch();
    				}else{
    					life--;
    				}
    			}
    			if(life <= 0){
    				system("cls");
    				enter(14);
    				kong(40);
    				printf("game over!");
    				printf("\n");
    				kong(40);
    				printf("your score is:%d", mxscore);
    				printf("\n");
    				kong(40);
    				char sure = 'n';
    				int flag = 1;
    				while(sure == 'n'){
    					if(flag){
    						flag = 0;
    					}else{
    						printf("\n");
    						kong(40);
    					}
    					printf("again?(y or n)");
    					xuan = getch();
    					if(xuan == 'y'){
    						system("cls");
    						life = 3;
    						levels = 1;
    						score = 0;
    						num = 0;
    						break;
    					}
    					system("cls");
    					enter(15);
    					kong(40);
    					printf("are you sure?(y or n)");
    					sure = getch();
    					if(sure == 'y'){
    						exit(0);
    					}
    				}
    				system("cls");
    				enter(15);
    				kong(10);
    				printf("请选择模式:a.入门, b.新手, c.中等, d.高手, e.大佬, f.递进, g.自定义");	
    				xx = getch();
    				if(xx == 'g'){
    					system("cls");
    					enter(15);
    					kong(40);
    					cout << "请输入时间隔(ms):";
    					cin >> shi;
    				}
    				break;
    			}
    		}
    	}
    	
    	return 0;
    } 
    
    
    
    
    
    
    
    

    开灯游戏:

    #include <bits/stdc++.h>
    
    using namespace std;
    
    int a[1010][1010];
    
    int main (){
    	int n;
    	for(int i = 1; i <= 40; i++){
    		cout << " ";
    	}
    	cout << "开灯游戏:按下按钮后它的上下左右与它自己取反。";
    	cout << endl;
    	for(int i = 1; i <= 40; i++){
    		cout << " ";
    	}
    	cout << "请输入开灯游戏的阶数:";
    	cin >> n;
    	for(int i = 1; i <= n; i++){
    		for(int j = 1; j <= n; j++){
    			a[i][j] = 0;
    		}
    	}
    	int flag = 1;
    	while(flag){
    		for(int i = 1; i <= n; i++){
    			for(int j = 1; j <= 40; j++){
    				cout << " ";
    			}
    			for(int j = 1; j <= n; j++){ 
    				cout << a[i][j] << " ";
    			}
    			cout << endl;
    		}
    		for(int i = 1; i <= 40; i++){
    			cout << " ";
    		}
    		int x, y;
    		cout << "请输入按下的行和列:"; 
    		cin >> x >> y;
    		system("cls");
    		a[x][y] = !a[x][y];
    		a[x][y - 1] = !a[x][y - 1];
    		a[x][y + 1] = !a[x][y + 1];
    		a[x - 1][y] = !a[x - 1][y];
    		a[x + 1][y] = !a[x + 1][y];
    		int f = 1;
    		for(int i = 1; i <= n; i++){
    			for(int j = 1; j <= n; j++){
    				if(a[i][j] != 1){
    					f = 0;
    				}
    			}
    		}
    		if(f){
    			flag = 0;
    		}
    	}
    	for(int i = 1; i <= n; i++){
    		for(int j = 1; j <= 40; j++){
    			cout << " ";
    		}
    		for(int j = 1; j <= n; j++){ 
    			cout << a[i][j] << " ";
    		}
    		cout << endl;
    	}
    	for(int j = 1; j <= 40; j++){
    		cout << " ";
    	}
    	cout << "恭喜你通过了" << n << "阶开灯问题";
    	
    	return 0; 
    }
    
    

    买二送一

    石头剪子布小游戏

    #include<bits/stdc++.h>
    #include"windows.h"
    
    using namespace std;
    
    int main(){
    	cout << "请输入你要玩的局数"; 
    	int n;
    	cin >> n;
    	int p1score = 0;
    	int p2score = 0;
    	for(int i = 1; i <= n; i++){
    		char p1;
    		cout << "请输入P1出的东西(石头 = s, 剪刀 = j, 布 = b)";
    		cin >> p1;
    		system("cls");
    		char p2;
    		cout << "请输入P2出的东西(石头 = s, 剪刀 = j, 布 = b)";
    		cin >> p2;
    		system("cls");
    		if(p1 == 's'){
    			if(p2 == 'j'){
    				p1score++;
    				cout << "P1 win" << endl;
    			}else if(p2 == 'b'){
    				p2score++;
    				cout << "P2 win" << endl;
    			}else{
    				cout << "NO win" << endl;
    			}
    		}
    		if(p1 == 'j'){
    			if(p2 == 'b'){
    				p1score++;
    				cout << "P1 win" << endl;
    			}else if(p2 == 's'){
    				p2score++;
    				cout << "P2 win" << endl;
    			}else{
    				cout << "NO win" << endl;
    			}
    		}
    		if(p1 == 'b'){
    			if(p2 == 's'){
    				p1score++;
    				cout << "P1 win" << endl;
    			}else if(p2 == 'j'){
    				p2score++;
    				cout << "P2 win" << endl;
    			}else{
    				cout << "NO win" << endl;
    			}
    		}
    		cout << p1score << " " << p2score << endl;
    		Sleep(1000);
    	}
    	if(p1score > p2score){
    		cout << "P1 win!";
    	}
    	if(p1score < p2score){
    		cout << "P2 win!";
    	}
    	if(p1score == p2score){
    		cout << "NO win";
    	}
    	
    	return 0;
    } 
    
    

    运气小游戏

    #include<bits/stdc++.h>
    
    using namespace std;
    
    int main(){
    	double score = 5;
    	double mxscore = 0;
    	while(score){
    		if(score <= 0){
    			break; 
    		}
    		srand(static_cast<unsigned int>(time(0)));
    		int num = rand() % 5 + 1;
    		cout << "请输入一个1到5的数:";
    		int cai;
    		cin >> cai;
    		if(num == cai){
    			score += 1;
    			cout << "好厉害,猜对了分数加1!" << endl;
    			cout << "score:" << score << endl;
    		}else if(cai < 1 || cai > 5){
    			score -= 2;
    			cout << "你行不行呀细狗,怎么填了个范围外的数啊~" << endl;
    			cout << "分数减2" << endl;
    			cout << "score:" << score << endl; 
    		}else{
    			score -= 0.5;
    			cout << "猜错了,菜就多练!" << endl;
    			cout << "分数减0.5" << endl;
    			cout << "score:" << score << endl; 
    		}
    		mxscore = max(score, mxscore);
    	}
    	if(mxscore == 4.5){
    		cout << "分数低于(等于)0,最高分:" << mxscore << ",游戏结束" << endl << 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菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜菜!";
    	}else if(mxscore <= 6){
    		cout << "分数低于0(等于),最高分:" << mxscore << ",游戏结束" << endl << "菜菜菜菜菜菜菜菜菜菜菜!";
    	}else if(mxscore <= 10){
    		cout << "分数低于0(等于),最高分:" << mxscore << ",游戏结束" << endl << "还不错";
    	}else{
    		cout << "分数低于0(等于),最高分:" << mxscore << ",游戏结束" << endl << "我举报有人开挂!";
    	} 
    	
    	
    	return 0;
    } 
    
    

    small目标:

    100

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    3500

    JNTM114514.想跳舞的鸡你太美

    题目背景

    鸡你太美非常想跳舞,但他不知怎么跳更吸引人,于是他来找你。

    题目描述

    共有n个数,代表鸡你太美该动作的美丽值

    输入格式

    输入一个正整数n,下面一行输入n个数。

    输出格式

    一个数表示最大美丽值(每一位用空格隔开,为了防止鸡你太美跟不上节奏。如果前面是负号,那么负号后面那一格不需要空,加号不用输出)

    样例数据

    输入数据

    4
    1 12 123 114514
    

    输出数据

    1 1 4 5 1 4
    

    数据范围

    对于前4个数据我们能保证每个数<=10的9次方

    对于前6个数据我们能保证每个数<=10的18次方

    对于前11个数据我们能保证每个数<=10的3000次方

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    This person is lazy and didn't write any solutions.
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