spoj#NSQUARE. NSquare Sum ( Easy )
NSquare Sum ( Easy )
Given two integers N ( N <= 10^18 ) and a prime number P ( 1 < P < 10^18 ), find the lowest number x such that there're not N integers greater or equal to 0 whose sum of squares is equal to x.
N = 2, P = 2 x = 3mod2 = 1
0 = 0² + 0² 1 = 1² + 0² 2 = 1² + 1² 4 = 2² + 0² |
Input
There're two integers N ( 1 <= N <= 10^18 ) and a prime number P ( 1 < P < 10^18 ). You have to print the answer modulo P.
Output
You have to print an integer x mod P ( -1 < x < 10^18 + 1 ) that satisfies the problem. If there's no number x, print "Impossible".
Example
Input: 1 3</p>Output: 2
Input: 13 7
Output: Impossible