codeforces#P776C. Molly's Chemicals

    ID: 28410 远端评测题 2000ms 512MiB 尝试: 1 已通过: 0 难度: 6 上传者: 标签>binary searchbrute forcedata structuresimplementationmath*1800

Molly's Chemicals

Description

Molly Hooper has n different kinds of chemicals arranged in a line. Each of the chemicals has an affection value, The i-th of them has affection value ai.

Molly wants Sherlock to fall in love with her. She intends to do this by mixing a contiguous segment of chemicals together to make a love potion with total affection value as a non-negative integer power of k. Total affection value of a continuous segment of chemicals is the sum of affection values of each chemical in that segment.

Help her to do so in finding the total number of such segments.

The first line of input contains two integers, n and k, the number of chemicals and the number, such that the total affection value is a non-negative power of this number k. (1 ≤ n ≤ 105, 1 ≤ |k| ≤ 10).

Next line contains n integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109) — affection values of chemicals.

Output a single integer — the number of valid segments.

Input

The first line of input contains two integers, n and k, the number of chemicals and the number, such that the total affection value is a non-negative power of this number k. (1 ≤ n ≤ 105, 1 ≤ |k| ≤ 10).

Next line contains n integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109) — affection values of chemicals.

Output

Output a single integer — the number of valid segments.

Samples

4 2
2 2 2 2

8

4 -3
3 -6 -3 12

3

Note

Do keep in mind that k0 = 1.

In the first sample, Molly can get following different affection values:

  • 2: segments [1, 1], [2, 2], [3, 3], [4, 4];

  • 4: segments [1, 2], [2, 3], [3, 4];

  • 6: segments [1, 3], [2, 4];

  • 8: segments [1, 4].

Out of these, 2, 4 and 8 are powers of k = 2. Therefore, the answer is 8.

In the second sample, Molly can choose segments [1, 2], [3, 3], [3, 4].