codeforces#P1575H. Holiday Wall Ornaments
Holiday Wall Ornaments
Description
The Winter holiday will be here soon. Mr. Chanek wants to decorate his house's wall with ornaments. The wall can be represented as a binary string $a$ of length $n$. His favorite nephew has another binary string $b$ of length $m$ ($m \leq n$).
Mr. Chanek's nephew loves the non-negative integer $k$. His nephew wants exactly $k$ occurrences of $b$ as substrings in $a$.
However, Mr. Chanek does not know the value of $k$. So, for each $k$ ($0 \leq k \leq n - m + 1$), find the minimum number of elements in $a$ that have to be changed such that there are exactly $k$ occurrences of $b$ in $a$.
A string $s$ occurs exactly $k$ times in $t$ if there are exactly $k$ different pairs $(p,q)$ such that we can obtain $s$ by deleting $p$ characters from the beginning and $q$ characters from the end of $t$.
The first line contains two integers $n$ and $m$ ($1 \leq m \leq n \leq 500$) — size of the binary string $a$ and $b$ respectively.
The second line contains a binary string $a$ of length $n$.
The third line contains a binary string $b$ of length $m$.
Output $n - m + 2$ integers — the $(k+1)$-th integer denotes the minimal number of elements in $a$ that have to be changed so there are exactly $k$ occurrences of $b$ as a substring in $a$.
Input
The first line contains two integers $n$ and $m$ ($1 \leq m \leq n \leq 500$) — size of the binary string $a$ and $b$ respectively.
The second line contains a binary string $a$ of length $n$.
The third line contains a binary string $b$ of length $m$.
Output
Output $n - m + 2$ integers — the $(k+1)$-th integer denotes the minimal number of elements in $a$ that have to be changed so there are exactly $k$ occurrences of $b$ as a substring in $a$.
Samples
9 3
100101011
101
1 1 0 1 6 -1 -1 -1
Note
For $k = 0$, to make the string $a$ have no occurrence of 101, you can do one character change as follows.
100101011 $\rightarrow$ 100100011
For $k = 1$, you can also change a single character.
100101011 $\rightarrow$ 100001011
For $k = 2$, no changes are needed.