Buy the String
Description
You are given four integers $n$, $c_0$, $c_1$ and $h$ and a binary string $s$ of length $n$.
A binary string is a string consisting of characters $0$ and $1$.
You can change any character of the string $s$ (the string should be still binary after the change). You should pay $h$ coins for each change.
After some changes (possibly zero) you want to buy the string. To buy the string you should buy all its characters. To buy the character $0$ you should pay $c_0$ coins, to buy the character $1$ you should pay $c_1$ coins.
Find the minimum number of coins needed to buy the string.
The first line contains a single integer $t$ ($1 \leq t \leq 10$) — the number of test cases. Next $2t$ lines contain descriptions of test cases.
The first line of the description of each test case contains four integers $n$, $c_{0}$, $c_{1}$, $h$ ($1 \leq n, c_{0}, c_{1}, h \leq 1000$).
The second line of the description of each test case contains the binary string $s$ of length $n$.
For each test case print a single integer — the minimum number of coins needed to buy the string.
Input
The first line contains a single integer $t$ ($1 \leq t \leq 10$) — the number of test cases. Next $2t$ lines contain descriptions of test cases.
The first line of the description of each test case contains four integers $n$, $c_{0}$, $c_{1}$, $h$ ($1 \leq n, c_{0}, c_{1}, h \leq 1000$).
The second line of the description of each test case contains the binary string $s$ of length $n$.
Output
For each test case print a single integer — the minimum number of coins needed to buy the string.
Samples
6
3 1 1 1
100
5 10 100 1
01010
5 10 1 1
11111
5 1 10 1
11111
12 2 1 10
101110110101
2 100 1 10
00
3
52
5
10
16
22
Note
In the first test case, you can buy all characters and pay $3$ coins, because both characters $0$ and $1$ costs $1$ coin.
In the second test case, you can firstly change $2$-nd and $4$-th symbols of the string from $1$ to $0$ and pay $2$ coins for that. Your string will be $00000$. After that, you can buy the string and pay $5 \cdot 10 = 50$ coins for that. The total number of coins paid will be $2 + 50 = 52$.