1 条题解
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1
#include <bits/stdc++.h> using namespace std; const int MAXN = 2e3 + 5; const double inf = 1e17 + 5; int n, m, v, e, c[MAXN][2], mp[305][305]; double k[MAXN], dp[MAXN][MAXN][2], ans; inline int read() { char ch = getchar(); int u = 0, f = 1; while (!isdigit(ch)) {if (ch == '-')f = -1; ch = getchar();} while (isdigit(ch)) {u = u * 10 + ch - 48; ch = getchar();}return u * f; } int main(){ memset(mp, 63, sizeof(mp)); n = read(); m = read(); v = read(); e = read(); for (register int i = 1; i <= n; i++)c[i][0] = read(); for (register int i = 1; i <= n; i++)c[i][1] = read(); for (register int i = 1; i <= n; i++)scanf("%lf", &k[i]); for (register int i = 1; i <= e; i++){ int x = read(), y = read(), w = read(); mp[x][y] = mp[y][x] = min(mp[x][y], w); } for (register int k = 1; k <= v; k++) for (register int i = 1; i <= v; i++) for (register int j = 1; j <= v; j++) mp[i][j] = min(mp[i][j], mp[i][k] + mp[k][j]); for (register int i = 1; i <= v; i++)mp[i][i] = mp[i][0] = mp[0][i] = 0; for (register int i = 0; i <= n; i++) for (register int j = 0; j <= m; j++)dp[i][j][0] = dp[i][j][1] = inf; dp[1][0][0] = dp[1][1][1] = 0; for (register int i = 2; i <= n; i++){ dp[i][0][0] = dp[i - 1][0][0] + mp[c[i - 1][0]][c[i][0]]; for (register int j = 1; j <= min(i, m); j++){ int C1 = c[i - 1][0], C2 = c[i - 1][1], C3 = c[i][0], C4 = c[i][1]; dp[i][j][0] = min(dp[i][j][0], min(dp[i - 1][j][0] + mp[C1][C3], dp[i - 1][j][1] + mp[C1][C3] * (1 - k[i - 1]) + mp[C2][C3] * k[i - 1])); dp[i][j][1] = min(dp[i][j][1], min(dp[i - 1][j - 1][0] + mp[C1][C3] * (1 - k[i]) + mp[C1][C4] * k[i], dp[i - 1][j - 1][1] + mp[C2][C4] * k[i] * k[i - 1] + mp[C2][C3] * k[i - 1] * (1 - k[i]) + mp[C1][C4] * (1 - k[i - 1]) * k[i] + mp[C1][C3] * (1 - k[i - 1]) * (1 - k[i]))); } } ans = inf; for (register int i = 0; i <= m; i++)ans = min(ans, min(dp[n][i][0], dp[n][i][1])); printf("%.2lf", ans); return 0; }
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信息
- ID
- 251
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- (无)
- 递交数
- 4
- 已通过
- 3
- 上传者