1 条题解
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0
C :
#include<stdio.h> void main() { int f[20001]={0},o[31],i,j,v,n; scanf("%d%d",&v,&n); for (i=0;i<n;i++) scanf("%d",&o[i]); f[0]=1; for (i=0;i<n;i++) for (j=v;j>=0;j--) if (j-o[i]>=0) if (f[j-o[i]]) f[j]=1; for (j=v;j>=0;j--) if (f[j]) break; printf("%d",v-j); }
C++ :
#include<iostream> #include<string.h> #include<algorithm> using namespace std; int main(){ int V,n,w[35],f[20005]; cin>>V>>n; memset(f,0,sizeof(f)); for(int i=1;i<=n;i++) cin>>w[i]; for(int i=1;i<=n;i++){ for(int j=V;j>=w[i];j--){ f[j]=max(f[j],f[j-w[i]]+w[i]); } } cout<<V-f[V]<<endl; return 0; }
Pascal :
var f:array[0..20000]of boolean; v,m,i,j,o,max:longint; begin readln(v); readln(m); f[0]:=true; for i:=1 to m do begin readln(o); for j:=v downto 0 do if (j+o<=v)and(f[j]) then f[j+o]:=true; end; for j:=0 to v do if f[j] then max:=j; writeln(v-max); end.
Java :
import java.util.*; public class Main { public static void main(String[] args){ int v; int n; int[] a; Scanner sc= new Scanner(System.in); while(sc.hasNext()){ v=sc.nextInt(); n=sc.nextInt(); a=new int[n]; for(int i=0;i<n;i++) a[i]=sc.nextInt(); int result=inornot(a,0,v); System.out.println(result); } sc.close(); } public static int inornot(int[] a,int i,int v){ if(i>=a.length) return v; else{ if(a[i]>v){ return inornot(a,i+1,v); } else{ int n=v-a[i]; int m=inornot(a,i+1,n); int k=inornot(a,i+1,v); if(m<k) return m; else return k; } } } }
Python :
# coding=utf-8 def main(): V = int(input()) n = int(input()) vv = [] for _ in range(n): vv.append(int(input())) dp = [[0 for _ in range(V+1)] for _ in range(n)] for i in range(n): for j in range(1, V+1): if i == 0: if j - vv[i] >= 0: dp[i][j] = vv[i] else: if j - vv[i] >= 0: dp[i][j] = max(dp[i-1][j], dp[i-1][j - vv[i]] + vv[i]) else: dp[i][j] = dp[i-1][j] print(int(V - dp[n-1][V])) if __name__ == '__main__': main()
- 1
信息
- ID
- 210
- 时间
- 1000ms
- 内存
- 125MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者