100 Accepted
# | 状态 分数 | 耗时 | 内存占用 |
---|---|---|---|
#1 | Accepted 20 | 1ms | 288 KiB |
#2 | Accepted 20 | 1ms | 552 KiB |
#3 | Accepted 20 | 1ms | 288 KiB |
#4 | Accepted 20 | 1ms | 320 KiB |
#5 | Accepted 20 | 1ms | 288 KiB |
代码
#include <stdio.h>
#include <limits.h>
int main() {
int n;
int i, max, min;
scanf("%d", &n);
int numbers[n];
scanf("%d", &numbers[0]);
max = min = numbers[0];
for (i = 1; i < n; i++) {
scanf("%d", &numbers[i]);
if (numbers[i] > max) {
max = numbers[i];
}
if (numbers[i] < min) {
min = numbers[i];
}
}
int range = max - min;
printf("%d\n", range);
return 0;
}
信息
- 递交者
- 题目
- J0058 【深基4.习5】求极差 / 最大跨度值
- 语言
- C
- 代码长度
- 575 Bytes
- 递交时间
- 2024-5-10 19:32:46
- 评测时间
- 2024-5-10 19:32:47
- 分数
- 100
- 总耗时
- 6ms
- 峰值时间
- 1ms
- 峰值内存
- 552 KiB