2 条题解
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1
#include<bits/stdc++.h> using namespace std; int n; int m; const int N = 105; char a[N][N]; bool vis[N][N]; int ans; const int dx[] = {0,0,-1,1}; const int dy[] = {-1,1,0,0}; void dfs(int x,int y){ vis[x][y] = true; for(int i = 0;i<4;i++){ int nx = x + dx[i]; int ny = y + dy[i]; if(1<=nx&&nx<=n&&1<=ny&&ny<=m&&!vis[nx][ny]&&a[nx][ny]!='0'){ dfs(nx,ny); } } return ; } int main(){ cin>>n>>m; for(int i = 1;i<=n;i++){ for(int j = 1;j<=m;j++){ cin>>a[i][j]; } } for(int i = 1;i<=n;i++){ for(int j = 1;j<=m;j++){ if(!vis[i][j]&&a[i][j]!='0'){ ans++; vis[i][j] = true; dfs(i,j); } } } cout<<ans; return 0; }
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-4
#include<bits/stdc++.h> using namespace std;
int n,m,a[110][110],ans; int dx[4]={-1,0,1,0,}; int dy[4]={0,1,0,-1};
void dfs(int x,int y) { a[x][y]=0; for(int i=0;i<4;i++) { int px=x+dx[i]; int py=y+dy[i]; if(a[px][py]) dfs(px,py); } } int main () { cin>>n>>m; for (int i=1;i<=n;i++) for (int j=1;j<=m;j++) { char ch; cin>>ch; a[i][j]=ch-'0'; } for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) { if(a[i][j]) { ans++; dfs(i,j); } } cout<<ans<<endl; return 0; }
- 1
信息
- ID
- 450
- 时间
- 1000ms
- 内存
- 125MiB
- 难度
- 2
- 标签
- 递交数
- 155
- 已通过
- 78
- 上传者