2 条题解

  • 1
    @ 2023-10-10 19:56:09
    #include<bits/stdc++.h>
    using namespace std;
    int n;
    int m;
    const int N = 105;
    char a[N][N];
    bool vis[N][N];
    int ans;
    const int dx[] = {0,0,-1,1};
    const int dy[] = {-1,1,0,0};
    
    void dfs(int x,int y){
    	vis[x][y] = true;
    	for(int i = 0;i<4;i++){
    		int nx = x + dx[i];
    		int ny = y + dy[i];
    		if(1<=nx&&nx<=n&&1<=ny&&ny<=m&&!vis[nx][ny]&&a[nx][ny]!='0'){
    			dfs(nx,ny);
    		}
    	}
    	return ;
    }
    
    int main(){
    	cin>>n>>m;
    	for(int i = 1;i<=n;i++){
    		for(int j = 1;j<=m;j++){
    			cin>>a[i][j];
    		}
    	}
    	for(int i = 1;i<=n;i++){
    		for(int j = 1;j<=m;j++){
    			if(!vis[i][j]&&a[i][j]!='0'){
    				ans++;
    				vis[i][j] = true;
    				dfs(i,j);
    			}
    		}
    	}
    	cout<<ans;
    	return 0;
    }
    
    • -4
      @ 2023-7-20 22:29:44

      #include<bits/stdc++.h> using namespace std;

      int n,m,a[110][110],ans; int dx[4]={-1,0,1,0,}; int dy[4]={0,1,0,-1};

      void dfs(int x,int y) { a[x][y]=0; for(int i=0;i<4;i++) { int px=x+dx[i]; int py=y+dy[i]; if(a[px][py]) dfs(px,py); } } int main () { cin>>n>>m; for (int i=1;i<=n;i++) for (int j=1;j<=m;j++) { char ch; cin>>ch; a[i][j]=ch-'0'; } for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) { if(a[i][j]) { ans++; dfs(i,j); } } cout<<ans<<endl; return 0; }

      • 1

      信息

      ID
      450
      时间
      1000ms
      内存
      125MiB
      难度
      2
      标签
      递交数
      155
      已通过
      78
      上传者