1 条题解

  • 1
    @ 2022-7-14 19:39:14
    #include <bits/stdc++.h>
        #define vc vector
        #define INF ((int)(1e9))
        #define LINF ((ll)(1e18))
        #define pb push_back
        #define mp make_pair
        #define ll long long
        #define _tp template
        #define _tyn typename
        #define sint short int
        #define ull unsigned ll
        #define pii pair<int,int>
        #define uint unsigned int
        #define ms(_data) memset(_data,0,sizeof(_data))
        #define fin(_filename) freopen(_filename,"r",stdin)
        #define fout(_filename) freopen(_filename,"w",stdout)
        #define msn(_data,_num) memset(_data,_num,sizeof(_data))
        using namespace std;
        _tp<_tyn T>void mymax( T &_a , T _b ){ if( _a < _b ) _a = _b; }
        _tp<_tyn T>void mymin( T &_a , T _b ){ if( _a > _b ) _a = _b; }
        void print(int _x){printf("%d\n",_x);}
        void print(ll _x){printf("%I64d ",_x);}
        #define il inline
        il int in(){
            char c = getchar();
            int ret = 0;
            while( c < '0'  ||  c > '9' ) c = getchar();
            while( c >= '0'  &&  c <= '9' ){
                ret *= 10;
                ret += c-'0';
                c = getchar();
            }
            return ret;
        }
        il void read( int &x ){
            x = in();
        }
        il void read( int &x, int &y ){
            x = in(); y = in();
        }
        il void read( int &x1 , int &x2 , int &x3 ){
            x1 = in(); x2 = in(); x3 = in();
        }
        il void read( int &x1 , int &x2 , int &x3 , int &x4 ){
            x1 = in(); x2 = in(); x3 = in(); x4 = in();
        }
        /////////////////////////////////////////////////////////////////////
        /////////////////////////////////////////////////////////////////////
        #define MAXN 110
        struct Edge{
            int to,cap,rev;
            Edge(){}
            Edge( int tt , int cc , int rr ){
                to = tt;
                cap = cc;
                rev = rr;
            }
        };
        int n,m,s,t;
        vc<Edge> e[MAXN<<1];
        vc<Edge> inp[MAXN<<1];
        il void addedge( int f , int t , int c ){
            inp[f].pb( Edge(t,c,inp[t].size()) );
            inp[t].pb( Edge(f,0,inp[f].size()-1) );
            e[f].pb(Edge());
            e[t].pb(Edge());
        }
        il void f5(){
            for( int i = 1 ; i <= n+n+1 ; i++ )
                for( uint j = 0 ; j < inp[i].size() ; j++ )
                    e[i][j] = inp[i][j];
        }
        int lev[MAXN<<1];    //Level
        il void bfs( int st ){
            ms(lev);
            queue<int> q;
            q.push(st);
            lev[st] = 1;
            while( !q.empty() ){
                int now = q.front();
                q.pop();
                for( uint i = 0 ; i < e[now].size() ; i++ ){
                    if( e[now][i].cap <= 0 ) continue;
                    int v = e[now][i].to;
                    if( !lev[v] ){
                        lev[v] = lev[now]+1;
                        q.push(v);
                    }
                }
            }
        }
        bool vis[MAXN<<1];
        il int dfs( int pos , int flow ){
            if( pos == t ) return flow;
            for( uint i = 0 ; i < e[pos].size() ; i++ ){
                Edge x = e[pos][i];
                int u = x.to;
                if( vis[u] ) continue;
                if( x.cap <= 0 ) continue;
                if( lev[u] != lev[pos]+1 ) continue;
                vis[u] = 1;
                int tans = dfs( u , min(flow,x.cap) );
                vis[u] = 0;
                if( tans > 0 ){
                    e[pos][i].cap -= tans;
                    e[u][x.rev].cap += tans;
                    return tans;
                }
            }
            return 0;
        }
        int ans = 0;
        int main(){
            read(n,m,s,t);
            for( int i = 1 ; i <= n ; i++ ){
                addedge(i,n+i,1);
            }
            for( int i = 1 ; i <= m ; i++ ){
                int a,b;
                read(a,b);
                addedge(a+n,b,INF);
                addedge(b+n,a,INF);
            }
            f5();
            while(1){
                bfs(s+n);
                if( !lev[t] ) break;
                ms(vis);
                int tans;
                while( ( tans = dfs(s+n,INF) ) > 0 ){
                    ans += tans;
                    ms(vis);
                }
                //cout << "[Tans] " << tans << endl;
            }
            printf("%d\n",ans);
            return 0;
        }
    
    • 1

    [USACO5.4] 奶牛的电信Telecowmunication

    信息

    ID
    346
    时间
    1000ms
    内存
    125MiB
    难度
    5
    标签
    递交数
    4
    已通过
    4
    上传者