1 条题解
-
1
#include<bits/stdc++.h> using namespace std; int main() { int a; cin >> a; int N = a * 2 + 1; int n[N]; for (int i = 0; i < N; i++) { cout<<" "; for (int j = i; j < N - i; j++) n[j] = a; for (int j = N - i - 1; j <= i - 1; j++) n[j] = -a; for (int j = 0; j < N; j++) cout << n[j] << " "; cout << endl; --a; } return 0; }
#include<bits/stdc++.h> using namespace std; int main() { int a; cin >> a; int N = a * 2 + 1; int n[N]; for (int i = 0; i < N; i++) { cout<<" "; for (int j = i; j < N - i; j++) n[j] = a; for (int j = N - i - 1; j <= i - 1; j++) n[j] = -a; for (int j = 0; j < N; j++) cout << n[j] << " "; cout << endl; --a; } return 0; }
- 1
信息
- ID
- 366
- 时间
- 1000ms
- 内存
- 16MiB
- 难度
- 2
- 标签
- 递交数
- 48
- 已通过
- 30
- 上传者