1 条题解
-
0
区间DP,破环成链
#include <bits/stdc++.h> using namespace std; const int N = 210, INF = 0x3f3f3f3f, MOD = 1E9 + 7; int n, w[N], f[N][N]; int main() { cin >> n; for (int i = 1; i <= n; i++) { cin >> w[i], w[i + n] = w[i]; } for (int len = 3; len <= n + 1; len++) for (int l = 1; l + len - 1 <= 2 * n; l++) { int r = l + len - 1; for (int k = l + 1; k < r; k++) { f[l][r] = max(f[l][r], f[l][k] + f[k][r] + w[l] * w[k] * w[r]); } } int res = 0; for (int i = 1; i <= n; i++) res = max(res, f[i][i + n]); cout << res; return 0; }
- 1
信息
- ID
- 468
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者