1 条题解
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0
区间DP,破环成链
#include <bits/stdc++.h> using namespace std; const int N = 410, INF = 0x3f3f3f3f, MOD = 1E9 + 7; int n, w[N], s[N], f[N][N], g[N][N]; int main() { cin >> n; for (int i = 1; i <= n; i++) { cin >> w[i], w[i + n] = w[i]; } for (int i = 1; i <= 2 * n; i++) s[i] = s[i - 1] + w[i]; memset(f, 0x3f, sizeof f); memset(g, -0x3f, sizeof g); for (int len = 1; len <= n; len++) for (int l = 1; l + len - 1 <= 2 * n; l++) { int r = l + len - 1; if (len == 1) { f[l][r] = g[l][r] = 0; continue; } for (int k = l; k < r; k++) { f[l][r] = min(f[l][r], f[l][k] + f[k + 1][r] + s[r] - s[l - 1]); g[l][r] = max(g[l][r], g[l][k] + g[k + 1][r] + s[r] - s[l - 1]); } } int minv = INF, maxv = -INF; for (int i = 1; i <= n; i++) { minv = min(minv, f[i][i + n - 1]); maxv = max(maxv, g[i][i + n - 1]); } cout << minv << endl << maxv; return 0; }
- 1
信息
- ID
- 467
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 17
- 已通过
- 1
- 上传者