1 条题解

  • 0
    @ 2024-10-10 19:43:13

    区间DP,破环成链

    #include <bits/stdc++.h>
    using namespace std;
    const int N = 410, INF = 0x3f3f3f3f, MOD = 1E9 + 7;
    int n, w[N], s[N], f[N][N], g[N][N];
    
    int main() {
        cin >> n;
        for (int i = 1; i <= n; i++) {
            cin >> w[i], w[i + n] = w[i];
        }
        for (int i = 1; i <= 2 * n; i++)
            s[i] = s[i - 1] + w[i];
        memset(f, 0x3f, sizeof f);
        memset(g, -0x3f, sizeof g);
        for (int len = 1; len <= n; len++)
            for (int l = 1; l + len - 1 <= 2 * n; l++) {
                int r = l + len - 1;
                if (len == 1) {
                    f[l][r] = g[l][r] = 0; continue;
                }
                for (int k = l; k < r; k++) {
                    f[l][r] = min(f[l][r], f[l][k] + f[k + 1][r] + s[r] - s[l - 1]);
                    g[l][r] = max(g[l][r], g[l][k] + g[k + 1][r] + s[r] - s[l - 1]);
                }
            }
        int minv = INF, maxv = -INF;
        for (int i = 1; i <= n; i++) {
            minv = min(minv, f[i][i + n - 1]);
            maxv = max(maxv, g[i][i + n - 1]);
        }
        cout << minv << endl << maxv;
        return 0;
    }
    
    • 1

    信息

    ID
    467
    时间
    1000ms
    内存
    512MiB
    难度
    10
    标签
    递交数
    17
    已通过
    1
    上传者