1 条题解
-
0
#include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 1e6 + 10, INF = 0x3f3f3f3f, MOD = 1E9 + 7; ll n, m, a[N], ans; int main(int argc, char* argv[]) { cin >> n >> m; for (int i = 1; i <= n; i++) cin >> a[i]; for (int i = 1; i <= n; i++) a[i] += a[i - 1]; while (m--) { int l, r; cin >> l >> r; if (l > r) swap(l, r); cout << a[r] - a[l - 1] << endl; } return 0; }
- 1
信息
- ID
- 422
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 7
- 标签
- (无)
- 递交数
- 423
- 已通过
- 93
- 上传者