1 条题解
-
0
二维费用
#include <bits/stdc++.h> using namespace std; typedef long long ll; const int inf = 0x3f3f3f3f, MOD = 1E9 + 7; const int N = 1e3 + 5, M = 105; int n, m, q, v1[N], v2[N], w[N], f[M][M]; int main(int argc, char* argv[]) { cin >> n >> m >> q; for (int i = 1; i <= n; i++) cin >> v1[i] >> v2[i] >> w[i]; for (int i = 1; i <= n; i++) for (int j = m; j >= v1[i]; j--) for (int k = q; k >= v2[i]; k--) f[j][k] = max(f[j][k], f[j - v1[i]][k - v2[i]] + w[i]); cout << f[m][q]; return 0; }
- 1
信息
- ID
- 360
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 1
- 标签
- 递交数
- 126
- 已通过
- 98
- 上传者