1 条题解

  • 0
    @ 2024-11-25 10:56:26

    转为01背包

    #include <bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    const int INF = 0x3f3f3f3f, MOD = 1E9 + 7;
    const int N = 1e3 * 20 + 10, M = 1e3 + 5;
    int n, m, cnt, v[N], w[N], f[M];
    int main(int argc, char* argv[]) {
        cin >> n >> m;
        for (int i = 1,a,b,c; i <= n; i++) {
            cin >> a >> b >> c;
            if (c == -1) c = m / a;
            int base = 1;
            while (c >= base) {
                v[++cnt] = a * base, w[cnt] = b * base;
                c -= base, base <<= 1;
            }
            if (c)
                v[++cnt] = a * c, w[cnt] = b * c;
        }
    
        for (int i = 1; i <= cnt; i++)
            for (int j = m; j >= v[i]; j--)
                f[j] = max(f[j], f[j - v[i]] + w[i]);
        cout << f[m];
        return 0;
    }
    
    • 1

    信息

    ID
    358
    时间
    1000ms
    内存
    256MiB
    难度
    2
    标签
    递交数
    156
    已通过
    97
    上传者