1 条题解
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0
线段树
#include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 1e5 + 10, INF = 0x3f3f3f3f; int n, m, q, a[N]; struct Node { int l, r; ll x, y, sum; } tr[N << 2]; void pushup(Node& u, Node& l, Node& r) { u.sum = (l.sum + r.sum) % m; } void pushup(int u) { pushup(tr[u], tr[u << 1], tr[u << 1 | 1]); } void pushdown(int u) { if (tr[u].x != 1) { tr[u << 1].x = (tr[u << 1].x * tr[u].x) % m; tr[u << 1].y = (tr[u << 1].y * tr[u].x) % m; tr[u << 1].sum = (tr[u << 1].sum * tr[u].x) % m; tr[u << 1 | 1].x = (tr[u << 1 | 1].x * tr[u].x) % m; tr[u << 1 | 1].y = (tr[u << 1 | 1].y * tr[u].x) % m; tr[u << 1 | 1].sum = (tr[u << 1 | 1].sum * tr[u].x) % m; tr[u].x = 1; } if (tr[u].y) { tr[u << 1].y = (tr[u << 1].y + tr[u].y) % m; tr[u << 1].sum = (tr[u << 1].sum + tr[u].y * (tr[u << 1].r - tr[u << 1].l + 1) % m) % m; tr[u << 1 | 1].y = (tr[u << 1 | 1].y + tr[u].y) % m; tr[u << 1 | 1].sum = (tr[u << 1 | 1].sum + tr[u].y * (tr[u << 1 | 1].r - tr[u << 1 | 1].l + 1) % m) % m; tr[u].y = 0; } } void build(int u, int l, int r) { tr[u] = {l, r, 1, 0, 0}; if (l == r) { tr[u].sum = a[l]; return; } int mid = l + r >> 1; build(u << 1, l, mid), build(u << 1 | 1, mid + 1, r); pushup(u); } void modify(int u, int l, int r, ll x, ll y) { if (l <= tr[u].l && r >= tr[u].r) { tr[u].x = (tr[u].x * x) % m; tr[u].y = (tr[u].y * x) % m; tr[u].sum = (tr[u].sum * x) % m; tr[u].y = (tr[u].y + y) % m; tr[u].sum = (tr[u].sum + y * (tr[u].r - tr[u].l + 1) % m) % m; return; } pushdown(u); int mid = tr[u].l + tr[u].r >> 1; if (l <= mid) modify(u << 1, l, r, x, y); if (r > mid) modify(u << 1 | 1, l, r, x, y); pushup(u); } Node query(int u, int l, int r) { if (l <= tr[u].l && r >= tr[u].r) return tr[u]; pushdown(u); int mid = tr[u].l + tr[u].r >> 1; Node res, left = {0, 0, 0, 0, 0}, right = {0, 0, 0, 0, 0}; if (l <= mid) left = query(u << 1, l, r); if (r > mid) right = query(u << 1 | 1, l, r); pushup(res, left, right); return res; } int main() { scanf("%d%d", &n,&m); for (int i = 1; i <= n; i++) scanf("%d", &a[i]); build(1, 1, n); int op, x, y, k; scanf("%d",&q); while (q--) { scanf("%d%d%d", &op, &x, &y); if (op != 3) scanf("%d", &k); if (op == 1) modify(1, x, y, k, 0); if (op == 2) modify(1, x, y, 1, k); if (op == 3) printf("%lld\n", query(1, x, y).sum % m); } return 0; }
- 1
信息
- ID
- 1676
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 10
- 标签
- 递交数
- 4
- 已通过
- 1
- 上传者