Score : $600$ points

Problem Statement

We have $N$ cards numbered $1$ to $N$. Card $i$ has an integer $A_i$ written on the front and an integer $B_i$ written on the back. Here, $\sum_{i=1}^N (A_i + B_i) = M$. For each $k=0,1,2,...,M$, solve the following problem.

The $N$ cards are arranged so that their front sides are visible. You may choose between $0$ and $N$ cards (inclusive) and flip them. To make the sum of the visible numbers equal to $k$, at least how many cards must be flipped? Print this number of cards. If there is no way to flip cards to make the sum of the visible numbers equal to $k$, print $-1$ instead.

Constraints

• $1 \leq N \leq 2 \times 10^5$
• $0 \leq M \leq 2 \times 10^5$
• $0 \leq A_i, B_i \leq M$
• $\sum_{i=1}^N (A_i + B_i) = M$
• All values in the input are integers.

Input

The input is given from Standard Input in the following format:

$N$ $M$

$A_1$ $B_1$

$A_2$ $B_2$

$\vdots$

$A_N$ $B_N$

Output

Print $M+1$ lines. The $i$-th line should contain the answer for $k=i-1$.

3 6
0 2
1 0
0 3

1
0
2
1
1
3
2

For $k=0$, for instance, flipping just card $2$ makes the sum of the visible numbers $0+0+0=0$. This choice is optimal. For $k=5$, flipping all cards makes the sum of the visible numbers $2+0+3=5$. This choice is optimal.

2 3
1 1
0 1

-1
0
1
-1

5 12
0 1
0 3
1 0
0 5
0 2

1
0
1
1
1
2
1
2
2
2
3
3
4