Score : $400$ points

Problem Statement

Given are a string $X$ consisting of 0 through 9, and an integer $M$.

Let $d$ be the greatest digit in $X$.

How many different integers not greater than $M$ can be obtained by choosing an integer $n$ not less than $d+1$ and seeing $X$ as a base-$n$ number?

Constraints

• $X$ consists of 0 through 9.
• The length of $X$ is between $1$ and $60$ (inclusive).
• $X$ does not begin with a 0.
• $1 \leq M \leq 10^{18}$

Input

Input is given from Standard Input in the following format:

$X$

$M$

Output

Print the answer.

22
10

2

The greatest digit in $X$ is 2.

• By seeing $X$ as a base-$3$ number, we get $8$.
• By seeing $X$ as a base-$4$ number, we get $10$.

These two values are the only ones that we can obtain and are not greater than $10$.

999
1500

3

The greatest digit in $X$ is 9.

• By seeing $X$ as a base-$10$ number, we get $999$.
• By seeing $X$ as a base-$11$ number, we get $1197$.
• By seeing $X$ as a base-$12$ number, we get $1413$.

These three values are the only ones that we can obtain and are not greater than $1500$.

100000000000000000000000000000000000000000000000000000000000
1000000000000000000

1

By seeing $X$ as a base-$2$ number, we get $576460752303423488$, which is the only value that we can obtain and are not greater than $1000000000000000000$.