2 条题解
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0
[NOIP 2013 普及组] 计数问题
#include <iostream> using namespace std; int countDigit(int n,int x) { int count = 0; for(int base = 1;base<=n;base*=10) { int high = n/(base*10); int low = n%base; int curr = (n/base) % 10; if(x == 0){ if(high>0) { high--; } else { break; } } count += high * base; if(curr == x) { count += low + 1; } else if(curr > x) { count += base; } } return count; } int main() { int n,x; cin>>n>>x; cout<< countDigit( n, x) << endl; return 0; }
- 1
信息
- ID
- 6033
- 时间
- 1000ms
- 内存
- 125MiB
- 难度
- 1
- 标签
- 递交数
- 392
- 已通过
- 230
- 上传者