2 solutions

  • 1

    #include<bits/stdc++.h> using namespace std; long long n, i; double num, s; int main() {

    cin >> n;
    for(i = 0;i < n;i++)
    {
        cin >> num;
        s += num;
    }
    cout << fixed << setprecision(2) << s / n;
    return 0;
    

    }****

    • 0
      @ 2024-10-25 14:40:38
      #include <iostream>
      #include <iomanip>
      using namespace std;
      int main() {
      	double n,a,sum = 0,ans = 0;
      	cin >> n;
      	for (int i = 1;i <= n;i++) {
      		cin >> a;
      		sum += a;
      	}
      	ans = sum / n;
      	cout << fixed << setprecision(2) << ans << endl;
      	return 0;
      }
      
      • 1

      Information

      ID
      4504
      Time
      1000ms
      Memory
      128MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      90
      Accepted
      53
      Uploaded By