4 solutions

  • 1
    @ 2025-7-15 10:44:30
    #include <bits/stdc++.h>
     using namespace std;
      int main() {
        double x1, y1, x2, y2, x3, y3;
        cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
        double r1 = sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));
        double r2 = sqrt((x3 - x1) * (x3 - x1) + (y3 - y1) * (y3 - y1));
         double r3 = sqrt((x2 - x3) * (x2 - x3) + (y2 - y3) * (y2 - y3));
        double p = (r1 + r2 + r3) / 2.0; double s = sqrt(p * (p - r1) * (p - r2) * (p - r3)); printf("%.2f", s);
    return 0; 
    }
    
    • 1
      @ 2024-12-16 22:00:40

      #include<bits/stdc++.h> using namespace std; int main(){ double x,y,xx,yy,xxx,yyy,a; cin>>x>>y>>xx>>yy>>xxx>>yyy; a=(xx-x)*(yyy-y); a=a/2; cout<<fixed<<setprecision(2)<<a; return 0; }

      • 1

        #include <bits/stdc++.h> using namespace std; int main() { double x1, y1, x2, y2, x3, y3; cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3; double r1 = sqrt((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1)); double r2 = sqrt((x3 - x1) * (x3 - x1) + (y3 - y1) * (y3 - y1)); double r3 = sqrt((x2 - x3) * (x2 - x3) + (y2 - y3) * (y2 - y3)); double p = (r1 + r2 + r3) / 2.0; double s = sqrt(p * (p - r1) * (p - r2) * (p - r3)); printf("%.2f", s); return 0; }

        • 0
          @ 2025-12-17 23:07:23

          #include <stdio.h> #include <math.h> // 用于浮点数绝对值函数fabs

          int main() { double x1, y1, x2, y2, x3, y3; // 读取6个双精度浮点数 scanf("%lf %lf %lf %lf %lf %lf", &x1, &y1, &x2, &y2, &x3, &y3); // 计算叉积的绝对值,再乘以0.5得到面积 double area = 0.5 * fabs( (x2 - x1) * (y3 - y1) - (y2 - y1) * (x3 - x1) ); // 输出保留两位小数 printf("%.2lf\n", area); return 0; }//关键点:向量叉乘

          • 1

          Information

          ID
          4481
          Time
          1000ms
          Memory
          512MiB
          Difficulty
          1
          Tags
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