又双要上代码了。。。

1.内置函数

#include <bits/stdc++.h>
using namespace std;

int main() {
    int c;
    cin >> c;
    cout << static_cast<char>(c) << endl;
    return 0;
}

2.强制转换

#include<bits/stdc++.h>
using namespace std;

int main(){
	int c;
	cin>>c;
	cout<<char(c); 
	return 0;
}

祝编程顺利！！

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;cin>>n;
    cout<<char(n);
    return 0;
}

强制类型转换

强转

#include<bits/stdc++.h>
#define yy return 0;
using namespace std;
int main(){
    int a;cin>>a;cout<<char(a);
    yy
}

#include <bits/stdc++.h> using namespace std;

int main() { int c; cin >> c; cout << static_cast(c) << endl; return 0; }

#include <iostream>
using namespace std;
int main(){
	char a;
	cin>>a;
	cout<<int(a);
	return 0;
}

#include<iostream>
using namespace std;
int main(){
    int a;
    cin>>a;
    std::cout << (char)a;

}

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;cin>>n;
    cout<<(char)(n);
    return 0;
}

强转好东西

luogu-B2018题解

luogu-B2017双倍经验

主要题意

输入一个数字，输出它相对的 ASCII 码转化的字符。

解题思路

输入数字后，直接强制转换为char类型输出。

上代码！

#include<bits/stdc++.h>
using namespace std;
int a;
int main()
{
    cin>>a;
    cout<<(char)a;
    return 0;
}

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