There are $n$ people (numbered from $1$ to $n$) signed up for a doctor's appointment. The doctor has to choose in which order he will appoint these people. The $i$-th patient should be appointed among the first $p_i$ people. There are also $m$ restrictions of the following format: the $i$-th restriction is denoted by two integers $(a_i, b_i)$ and means that the patient with the index $a_i$ should be appointed earlier than the patient with the index $b_i$.

For example, if $n = 4$, $p = [2, 3, 2, 4]$, $m = 1$, $a = [3]$ and $b = [1]$, then the only order of appointment of patients that does not violate the restrictions is $[3, 1, 2, 4]$. For $n =3$, $p = [3, 3, 3]$, $m = 0$, $a = []$ and $b = []$, any order of appointment is valid.

For each patient, calculate the minimum position in the order that they can have among all possible orderings that don't violate the restrictions.

The first line contains two integers $n$ and $m$ ($1 \le n \le 2000$; $0 \le m \le 2000$).

The second line contains $n$ integers $p_1, p_2, \dots, p_n$ ($1 \le p_i \le n$).

Then $m$ lines follow. The $i$-th of them contains two integers $a_i$ and $b_i$ ($1 \le a_i, b_i \le n$; $a_i \ne b_i$). All pairs of $(a_i, b_i)$ are distinct (i. e. if $i \ne j$, then either $a_i \ne a_j$, $b_i \ne b_j$, or both).

Additional constraint on the input: there is at least one valid order of patients.

Print $n$ integers, where $i$-th integer is equal to the minimum position of $i$-th patient in the order, among all valid orders. Positions in the order are numbered from $1$ to $n$.