atcoder#ABC244B. [ABC244B] Go Straight and Turn Right

[ABC244B] Go Straight and Turn Right

Score : 200200 points

Problem Statement

Consider an xyxy-plane. The positive direction of the xx-axis is in the direction of east, and the positive direction of the yy-axis is in the direction of north. Takahashi is initially at point (x,y)=(0,0)(x, y) = (0, 0) and facing east (in the positive direction of the xx-axis).

You are given a string T=t1t2tNT = t_1t_2\ldots t_N of length NN consisting of S and R. Takahashi will do the following move for each i=1,2,,Ni = 1, 2, \ldots, N in this order.

  • If ti=t_i = S, Takahashi advances in the current direction by distance 11.
  • If ti=t_i = R, Takahashi turns 9090 degrees clockwise without changing his position. As a result, Takahashi's direction changes as follows.- If he is facing east (in the positive direction of the xx-axis) before he turns, he will face south (in the negative direction of the yy-axis) after he turns.
    • If he is facing south (in the negative direction of the yy-axis) before he turns, he will face west (in the negative direction of the xx-axis) after he turns.
    • If he is facing west (in the negative direction of the xx-axis) before he turns, he will face north (in the positive direction of the yy-axis) after he turns.
    • If he is facing north (in the positive direction of the yy-axis) before he turns, he will face east (in the positive direction of the xx-axis) after he turns.

Print the coordinates Takahashi is at after all the steps above have been done.

Constraints

  • 1N1051 \leq N \leq 10^5
  • NN is an integer.
  • TT is a string of length NN consisting of S and R.

Input

Input is given from Standard Input in the following format:

NN

TT

Output

Print the coordinates (x,y)(x, y) Takahashi is at after all the steps described in the Problem Statement have been completed, in the following format, with a space in between:

xx yy

4
SSRS
2 -1

Takahashi is initially at (0,0)(0, 0) facing east. Then, he moves as follows.

  1. t1=t_1 = S, so he advances in the direction of east by distance 11, arriving at (1,0)(1, 0).
  2. t2=t_2 = S, so he advances in the direction of east by distance 11, arriving at (2,0)(2, 0).
  3. t3=t_3 = R, so he turns 9090 degrees clockwise, resulting in facing south.
  4. t4=t_4 = S, so he advances in the direction of south by distance 11, arriving at (2,1)(2, -1).

Thus, Takahashi's final position, (x,y)=(2,1)(x, y) = (2, -1), should be printed.

20
SRSRSSRSSSRSRRRRRSRR
0 1