100 atcoder#ABC157D. [ABC157D] Friend Suggestions

[ABC157D] Friend Suggestions

Score : 400400 points

Problem Statement

An SNS has NN users - User 11, User 22, \cdots, User NN.

Between these NN users, there are some relationships - MM friendships and KK blockships.

For each i=1,2,,Mi = 1, 2, \cdots, M, there is a bidirectional friendship between User AiA_i and User BiB_i.

For each i=1,2,,Ki = 1, 2, \cdots, K, there is a bidirectional blockship between User CiC_i and User DiD_i.

We define User aa to be a friend candidate for User bb when all of the following four conditions are satisfied:

  • aba \neq b.
  • There is not a friendship between User aa and User bb.
  • There is not a blockship between User aa and User bb.
  • There exists a sequence c0,c1,c2,,cLc_0, c_1, c_2, \cdots, c_L consisting of integers between 11 and NN (inclusive) such that c0=ac_0 = a, cL=bc_L = b, and there is a friendship between User cic_i and ci+1c_{i+1} for each i=0,1,,L1i = 0, 1, \cdots, L - 1.

For each user i=1,2,...Ni = 1, 2, ... N, how many friend candidates does it have?

Constraints

  • All values in input are integers.
  • 2N1052 \leq N \leq 10^5
  • 0M1050 \leq M \leq 10^5
  • 0K1050 \leq K \leq 10^5
  • 1Ai,BiN1 \leq A_i, B_i \leq N
  • AiBiA_i \neq B_i
  • 1Ci,DiN1 \leq C_i, D_i \leq N
  • CiDiC_i \neq D_i
  • (Ai,Bi)(Aj,Bj)(ij)(A_i, B_i) \neq (A_j, B_j) (i \neq j)
  • (Ai,Bi)(Bj,Aj)(A_i, B_i) \neq (B_j, A_j)
  • (Ci,Di)(Cj,Dj)(ij)(C_i, D_i) \neq (C_j, D_j) (i \neq j)
  • (Ci,Di)(Dj,Cj)(C_i, D_i) \neq (D_j, C_j)
  • (Ai,Bi)(Cj,Dj)(A_i, B_i) \neq (C_j, D_j)
  • (Ai,Bi)(Dj,Cj)(A_i, B_i) \neq (D_j, C_j)

Input

Input is given from Standard Input in the following format:

NN MM KK

A1A_1 B1B_1

\vdots

AMA_M BMB_M

C1C_1 D1D_1

\vdots

CKC_K DKD_K

Output

Print the answers in order, with space in between.

4 4 1
2 1
1 3
3 2
3 4
4 1
0 1 0 1

There is a friendship between User 22 and 33, and between 33 and 44. Also, there is no friendship or blockship between User 22 and 44. Thus, User 44 is a friend candidate for User 22.

However, neither User 11 or 33 is a friend candidate for User 22, so User 22 has one friend candidate.

5 10 0
1 2
1 3
1 4
1 5
3 2
2 4
2 5
4 3
5 3
4 5
0 0 0 0 0

Everyone is a friend of everyone else and has no friend candidate.

10 9 3
10 1
6 7
8 2
2 5
8 4
7 3
10 9
6 4
5 8
2 6
7 5
3 1
1 3 5 4 3 3 3 3 1 0