5 solutions
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0
#include<bits/stdc++.h> using namespace std; int n,p,l=0,a[5000005],sum[5000005],x,y,z,ans=1e9; int main(){ cin>>n>>p; for(int i=1;i<=n;i++) { cin>>a[i]; } for(int i=1;i<=p;i++) { cin>>x>>y>>z; sum[y]+=z; sum[x-1]-=z; } for(int i=n;i>=1;i--) { l+=sum[i]; a[i]+=l; ans=min(ans,a[i]); } cout<<ans; return 0; }
Information
- ID
- 6406
- Time
- 1000ms
- Memory
- 125MiB
- Difficulty
- 3
- Tags
- # Submissions
- 104
- Accepted
- 32
- Uploaded By