C语言解法 （数组运用，for循环中continue和break的使用）（新手求赞）

#include <stdio.h>
int main() {
    int n;
    scanf("%d", &n);
    int a[100];  

    for (int i = 0; i < n; i++) {
        scanf("%d", &a[i]);
    }

    int count = 0;

    for (int j = 0; j < n; j++) {
        int found = 0;
        for (int k = 0; k < n; k++) {
            if (k == j) continue; 
            for (int m = 0; m < n; m++) {
                if (m == j || m == k) continue; 
                if (a[j] == a[k] + a[m]) {
                    count++;
                    found = 1;
                    break;
                }
            }
            if (found) break;
        }
    }

    printf("%d\n", count);

    return 0;
}