虽然这种简单题写个快读确实是大材小用， 但是有了快读，这个程序的主程序就可如python一般简洁

因此就有了这篇题解，大家就当学快读的写法吧qwq

#include <bits/stdc++.h>
using namespace std;
inline int read()
{
    int X = 0; bool f = false; char ch = getchar();
    while (ch > '9' || ch < '0') {f |= ch == '-'; ch = getchar();}
    while (ch <= '9' && ch >= '0') {X = (X << 3) + (X << 1) + (ch ^ 48); ch = getchar();}
    return f ? -X : X;
}
inline void write(int X)
{
    if (X == 0) {putchar('0'); return;}
    if (X < 0) {putchar('-'); X = -X;}
    short num[21], cnt = 0;
    while (X) {num[++cnt] = X % 10; X /= 10;}
    while (cnt) putchar(num[cnt--] ^ 48);
    return;
}
int main()
{
    write(read() + read());
    return 0;
}