2 solutions
-
0
请勿抄袭#include <iostream> #include <algorithm> using namespace std; typedef long long ll; const int N = 2e5 + 5; int n, x, a[N], dp[N], f[N], g[N], idx, ans1, ans2; int main() { while (cin >> x) a[++n] = x; f[++ans1] = a[1]; for (int i = 2; i <= n; ++i) { if (a[i] <= f[ans1]) f[++ans1] = a[i]; ................
Information
- ID
- 5078
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 6
- Tags
- # Submissions
- 187
- Accepted
- 46
- Uploaded By