这样就过了(换行，开long long,去缓冲区)

#include <bits/stdc++.h>
using namespace std;
int main(){
	ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    long long a;
    cin>>a;
    while(a!=1){
        if(a%2){
            cout<<a<<"*3+1="<<a*3+1<<"\n";
            a=a*3+1;
        }
        else{
            cout<<a<<"/2="<<a/2<<"\n";
            a/=2;
        }
    }
    cout<<"End";
    return 0;
}