100 Accepted
# | 状态 分数 | 耗时 | 内存占用 |
---|---|---|---|
#1 | Accepted 10 | 3ms | 504 KiB |
#2 | Accepted 10 | 3ms | 504 KiB |
#3 | Accepted 10 | 3ms | 504 KiB |
#4 | Accepted 10 | 3ms | 508 KiB |
#5 | Accepted 10 | 3ms | 500 KiB |
#6 | Accepted 10 | 3ms | 504 KiB |
#7 | Accepted 10 | 3ms | 504 KiB |
#8 | Accepted 10 | 3ms | 504 KiB |
#9 | Accepted 10 | 3ms | 504 KiB |
#10 | Accepted 10 | 2ms | 504 KiB |
代码
#include<bits/stdc++.h>
using namespace std;
int a[1145][514],n,x,y,s=0;
int main(){
cin>>n;
for(int i=1;i<=n;i++){
x=(n-i+1),y=0;
for(int j=1;j<=i;j++){
y++;
a[x][y]=++s;
//cout<<x<<" "<<y<<" "<<s<<" ";
}
//cout<<"\n";
for(int k=1;k<i;k++){
x++;
a[x][y]=++s;
//cout<<x<<" "<<y<<" "<<s<<" ";
}
//cout<<"\n";
}
//cout<<"\n\n\n";
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
cout<<setw(4)<<a[i][j];
}
cout<<"\n";
}
return 0;
}
信息
- 递交者
- 题目
- P369 练63.3 迂回方阵
- 语言
- C++17(O2)
- 代码长度
- 504 Bytes
- 递交时间
- 2025-4-23 10:02:53
- 评测时间
- 2025-4-23 10:02:54
- 分数
- 100
- 总耗时
- 27ms
- 峰值时间
- 3ms
- 峰值内存
- 508 KiB