100 Accepted
# | 状态 分数 | 耗时 | 内存占用 |
---|---|---|---|
#1 | Accepted 10 | 3ms | 536 KiB |
#2 | Accepted 10 | 3ms | 536 KiB |
#3 | Accepted 10 | 3ms | 536 KiB |
#4 | Accepted 10 | 3ms | 552 KiB |
#5 | Accepted 10 | 3ms | 320 KiB |
#6 | Accepted 10 | 3ms | 548 KiB |
#7 | Accepted 10 | 3ms | 516 KiB |
#8 | Accepted 10 | 3ms | 536 KiB |
#9 | Accepted 10 | 3ms | 324 KiB |
#10 | Accepted 10 | 3ms | 544 KiB |
代码
#include <iostream>
using namespace std;
int a[105][105],h,k=1,l,b=2,hy=0;
int main(){
int n;
cin >> n;
h=n-1;
for (int i = 0; i <= n-1; i++) {
h = n - hy;
l = 1;
for (; l != b;) {
a[h][l] = k++;
l++;
}
l--;
for (; h != n;) {
h++;
a[h][l] = k++;
}
b++;
hy++;
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
printf("%4d", a[i][j]);
}
cout << "\n";
}
}
信息
- 递交者
- 题目
- P369 练63.3 迂回方阵
- 语言
- C++11
- 代码长度
- 578 Bytes
- 递交时间
- 2025-2-14 21:06:59
- 评测时间
- 2025-2-14 21:07:01
- 分数
- 100
- 总耗时
- 30ms
- 峰值时间
- 3ms
- 峰值内存
- 552 KiB