100 Accepted
| # | 状态 分数 | 耗时 | 内存占用 |
|---|---|---|---|
| #1 | Accepted 5 | 1ms | 284 KiB |
| #2 | Accepted 5 | 1ms | 204 KiB |
| #3 | Accepted 5 | 1ms | 284 KiB |
| #4 | Accepted 5 | 1ms | 204 KiB |
| #5 | Accepted 5 | 1ms | 284 KiB |
| #6 | Accepted 5 | 1ms | 284 KiB |
| #7 | Accepted 5 | 1ms | 284 KiB |
| #8 | Accepted 5 | 1ms | 284 KiB |
| #9 | Accepted 5 | 1ms | 284 KiB |
| #10 | Accepted 5 | 1ms | 284 KiB |
| #11 | Accepted 5 | 1ms | 284 KiB |
| #12 | Accepted 5 | 1ms | 284 KiB |
| #13 | Accepted 5 | 1ms | 284 KiB |
| #14 | Accepted 5 | 1ms | 284 KiB |
| #15 | Accepted 5 | 1ms | 200 KiB |
| #16 | Accepted 5 | 1ms | 284 KiB |
| #17 | Accepted 5 | 1ms | 284 KiB |
| #18 | Accepted 5 | 1ms | 284 KiB |
| #19 | Accepted 5 | 1ms | 204 KiB |
| #20 | Accepted 5 | 1ms | 284 KiB |
代码
#include<stdio.h>
int main(){
int a,b,x,y,g,s,o,j;
scanf("%d %d",&a,&b);
for(int i=100;i>10;i--){
x=i/10;
y=i%10;
if(x+y==a&&x-y==b){
o=i;
}
}
g=o%10;
s=o/10;
if(g==0)
j=o;
else
j=g*10+s;
printf("%d",j);
return 0;
}信息
- 递交者
-
Guest
- 题目
- P199 【例33.2】 两位数
- 语言
- C
- 代码长度
- 307 Bytes
- 递交时间
- 2023-10-24 19:32:08
- 评测时间
- 2023-10-24 19:32:08
- 分数
- 100
- 总耗时
- 26ms
- 峰值时间
- 1ms
- 峰值内存
- 284 KiB