100 Accepted
| # | 状态 分数 | 耗时 | 内存占用 |
|---|---|---|---|
| #1 | Accepted 5 | 1ms | 204 KiB |
| #2 | Accepted 5 | 2ms | 284 KiB |
| #3 | Accepted 5 | 2ms | 284 KiB |
| #4 | Accepted 5 | 1ms | 284 KiB |
| #5 | Accepted 5 | 1ms | 284 KiB |
| #6 | Accepted 5 | 1ms | 284 KiB |
| #7 | Accepted 5 | 1ms | 284 KiB |
| #8 | Accepted 5 | 1ms | 284 KiB |
| #9 | Accepted 5 | 1ms | 284 KiB |
| #10 | Accepted 5 | 2ms | 284 KiB |
| #11 | Accepted 5 | 1ms | 228 KiB |
| #12 | Accepted 5 | 2ms | 284 KiB |
| #13 | Accepted 5 | 2ms | 200 KiB |
| #14 | Accepted 5 | 2ms | 284 KiB |
| #15 | Accepted 5 | 1ms | 284 KiB |
| #16 | Accepted 5 | 1ms | 284 KiB |
| #17 | Accepted 5 | 2ms | 284 KiB |
| #18 | Accepted 5 | 1ms | 284 KiB |
| #19 | Accepted 5 | 1ms | 284 KiB |
| #20 | Accepted 5 | 1ms | 284 KiB |
代码
#include<stdio.h>
int main()
{
int a,b;
scanf("%d",&a);
if(a>6)b=(a-6)*2;
else b=0;
printf("%d",b+a*5);
return 0;
}信息
- 递交者
-
Guest
- 题目
- P93 【例17.2】 蜗牛爬行
- 语言
- C
- 代码长度
- 124 Bytes
- 递交时间
- 2023-10-19 20:02:52
- 评测时间
- 2023-10-19 20:02:53
- 分数
- 100
- 总耗时
- 29ms
- 峰值时间
- 2ms
- 峰值内存
- 284 KiB