100 Accepted
# | 状态 分数 | 耗时 | 内存占用 |
---|---|---|---|
#1 | Accepted 5 | 3ms | 412 KiB |
#2 | Accepted 5 | 3ms | 412 KiB |
#3 | Accepted 5 | 4ms | 412 KiB |
#4 | Accepted 5 | 2ms | 412 KiB |
#5 | Accepted 5 | 3ms | 412 KiB |
#6 | Accepted 5 | 2ms | 412 KiB |
#7 | Accepted 5 | 4ms | 412 KiB |
#8 | Accepted 5 | 3ms | 412 KiB |
#9 | Accepted 5 | 4ms | 332 KiB |
#10 | Accepted 5 | 3ms | 412 KiB |
#11 | Accepted 5 | 3ms | 412 KiB |
#12 | Accepted 5 | 2ms | 412 KiB |
#13 | Accepted 5 | 3ms | 412 KiB |
#14 | Accepted 5 | 3ms | 412 KiB |
#15 | Accepted 5 | 3ms | 412 KiB |
#16 | Accepted 5 | 3ms | 328 KiB |
#17 | Accepted 5 | 3ms | 412 KiB |
#18 | Accepted 5 | 3ms | 412 KiB |
#19 | Accepted 5 | 3ms | 412 KiB |
#20 | Accepted 5 | 3ms | 412 KiB |
代码
#include<bits/stdc++.h>
using namespace std;
int main()
{int b,m;
char a;
cin>>a>>b;
if(a=='Z')
for(int i=1;i<=b;i++)
{for(int j=1;j<=b;j++)
{cout<<"*";}
cout<<endl;
}
else
{for(int k=1;k<=b;k++)
{for(int m=1;m<=b-k;m++)
{cout<<" ";
}
for(int n=1;n<=2*k-1;n++)
{cout<<"*";
}cout<<endl;
}
for(int o=1;o<=b-1;o++)
{for(int p=1;p<=o;p++)
cout<<" ";
for(int q=1;q<=2*(b-1)-1-(o-1)*2;q++)
cout<<"*";
cout<<endl;
}
}
return 0;
}
信息
- 递交者
- 题目
- P228 【例38.2】 图形输出
- 语言
- C++17(O2)
- 代码长度
- 457 Bytes
- 递交时间
- 2023-8-10 21:27:24
- 评测时间
- 2023-8-10 21:27:26
- 分数
- 100
- 总耗时
- 60ms
- 峰值时间
- 4ms
- 峰值内存
- 412 KiB