100 Accepted
# | 状态 分数 | 耗时 | 内存占用 |
---|---|---|---|
#1 | Accepted 5 | 4ms | 328 KiB |
#2 | Accepted 5 | 3ms | 412 KiB |
#3 | Accepted 5 | 3ms | 328 KiB |
#4 | Accepted 5 | 2ms | 412 KiB |
#5 | Accepted 5 | 3ms | 412 KiB |
#6 | Accepted 5 | 3ms | 412 KiB |
#7 | Accepted 5 | 3ms | 328 KiB |
#8 | Accepted 5 | 4ms | 412 KiB |
#9 | Accepted 5 | 3ms | 412 KiB |
#10 | Accepted 5 | 3ms | 424 KiB |
#11 | Accepted 5 | 3ms | 416 KiB |
#12 | Accepted 5 | 3ms | 404 KiB |
#13 | Accepted 5 | 3ms | 412 KiB |
#14 | Accepted 5 | 3ms | 412 KiB |
#15 | Accepted 5 | 3ms | 412 KiB |
#16 | Accepted 5 | 3ms | 412 KiB |
#17 | Accepted 5 | 3ms | 412 KiB |
#18 | Accepted 5 | 3ms | 412 KiB |
#19 | Accepted 5 | 3ms | 412 KiB |
#20 | Accepted 5 | 3ms | 412 KiB |
代码
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
char t;
cin >> t >> n;
if (t == 'L')
{
n = 2 * n - 1;
int cx = n / 2, cy = n / 2;
for (int i = 0; i < n; i ++ )
{
for (int j = 0; j < n; j ++ )
{
if (abs(i - cx) + abs(j - cy) <= n / 2)
cout << '*';
else
cout << ' ';
}
cout << endl;
}
}
else
{
for (int i = 0; i < n; i ++ )
{
for (int j = 0; j < n; j ++ )
cout << "*";
cout << endl;
}
}
return 0;
}
信息
- 递交者
- 题目
- P228 【例38.2】 图形输出
- 语言
- C++14(O2)
- 代码长度
- 611 Bytes
- 递交时间
- 2023-8-10 14:15:49
- 评测时间
- 2023-8-10 14:15:50
- 分数
- 100
- 总耗时
- 60ms
- 峰值时间
- 4ms
- 峰值内存
- 424 KiB