C++ :

#include <algorithm>
#include <iostream>
using namespace std;
#define  N 10
int p[N]={2,3,4,5,6,7,8,10,12,14};
int main()
{
	int r1,r2,r3,r4,c1,c2,c3,c4,d1,d2;//4行，4列和2对角线 
	do
	{
		r1=p[0]+p[1]+29;
		r2=11+p[2]+p[3]+p[4];
		r3=9+p[5]+p[6]+p[7];
		r4=16+p[8]+p[9];
		c1=25+p[2]+p[8];
		c2=15+p[0]+p[3]+p[5];
		c3=11+p[1]+p[6]+p[9];
		c4=14+p[4]+p[7];
		d1=17+p[3]+p[6];
		d2=24+p[5]+p[8];
		if(r1==r2&&r2==r3&&r3==r4&&r4==c1&c1==c2&&c2==c3&&c3==c4&&c4==d1&&d1==d2)
			cout<<p[7];
	}
	while(next_permutation(p,p+N));
	return 0;
}