1 条题解

  • 0
    @ 2021-6-15 1:39:19

    C++ :

    #include<cstdio>
    #include<string>
    #include<cstring>
    #include<iostream>
    #include<istream>
    using namespace std;
    const int maxn = 100;
    struct bign {
        int len, s[maxn];
        bign() { memset(s, 0, sizeof(s)); len = 1; }
        bign(int num) { *this = num; }
        bign(const char* num) { *this = num; }
        string str() const {
            string res = "";
            for (int i = 0; i < len; i++) res = (char)(s[i]+'0') + res;
            if (res == "") res = "0";
            return res;
        }
        bign operator = (const char* num) {
            len = strlen(num);
            for (int i = 0; i < len; i++) s[i] = num[len-i-1] - '0';
            return *this;
        }
        bign operator = (int num) {
            char s[maxn];
            sprintf(s, "%d", num);
            *this = s;
            return *this;
        }
        bign operator + (const bign& b) const {
            bign c;
            c.len = 0;
            for (int i = 0, g = 0; g || i < max(len, b.len); i++) {
                int x = g;
                if (i < len) x += s[i];
                if (i < b.len) x+=b.s[i];
                c.s[c.len++] = x % 10;
                g = x / 10;
            }
            return c;
        }
        bign operator += (const bign& b) {
            *this = *this + b;
            return *this;
        }
        bool operator < (const bign& b) const {
            if (len!=b.len) return len < b.len;
            for (int i = len-1; i >= 0; i--) 
                if (s[i]!=b.s[i]) return s[i] < b.s[i];
            return false;
        }
        bool operator > (const bign& b) const { return b < *this; }
        bool operator <= (const bign& b) const { return !(b < *this); }
        bool operator >= (const bign& b) const { return !(*this < b); }
        bool operator != (const bign& b) const { return b < *this || *this < b; }
        bool operator == (const bign& b) const { return !(b < *this) && !(*this < b); }
    };
    istream& operator >> (istream &in, bign& x) {
        string s;
        in >> s;
        return in;
    }
    ostream& operator << (ostream &out, const bign& x) {
        out << x.str();
        return out;
    }
    bign ans[210];
    int main() {
        int n;
        ans[1] = 2;
        for (int i = 2; i <= 200; i++) {
             ans[i] = ans[i-1] + ans[i-1] + 2;
    //       cout << ans[i] << endl;
        }
        while (cin >> n) cout << ans[n] << endl;
        return 0;
    }
    
    

    Pascal :

    var a,b:array[0..100] of integer;
        i,j,n:integer;
    begin
     read(n);
     b[100]:=1;
     for i:=1 to n do
      begin
       for j:=1 to 100 do b[j]:=b[j]*2;
       for j:=100 downto 1 do if b[j]>9 then
        begin
         b[j]:=b[j]-10;
         b[j-1]:=b[j-1]+1;
        end;
       for j:=1 to 100 do a[j]:=a[j]+b[j];
       for j:=100 downto 1 do if a[j]>9 then
        begin
         a[j]:=a[j]-10;
         a[j-1]:=a[j-1]+1;
         end;
       end;
     j:=1;
     while a[j]=0 do j:=j+1;
     for i:=j to 100 do write(a[i]);
    end.
    
    • 1

    信息

    ID
    256
    时间
    1000ms
    内存
    125MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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