1 条题解
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1
#include <cstdio> #include <cstring> #include <algorithm> #include <iostream> #include <vector> #include <cmath> #include <iterator> #define LL long long #define mem(a, b) memset(a, b, sizeof(a)) #define rep(i, a, b) for(int i = (a); i <= (b); i++) using namespace std; const int maxn = 20; const int INF = 10000000000; int N, A[maxn][maxn], B[maxn][maxn]; int query(int cur){ mem(B, 0); rep(j, 0, N-1){ if(cur & (1<<j)) B[0][j] = 1; else if(A[0][j] == 1) return INF; } rep(i, 1, N-1) rep(j, 0, N-1){ int sum = 0; if(i > 1) sum += B[i-2][j]; if(j > 0) sum += B[i-1][j-1]; if(j < N-1) sum += B[i-1][j+1]; B[i][j] = sum % 2; if(A[i][j] == 1 && B[i][j] == 0) return INF; } int cnt = 0; rep(i, 0, N-1) rep(j, 0, N-1) if(A[i][j] != B[i][j]) cnt++; return cnt; } int main(){ scanf("%d", &N); rep(i, 0, N-1) rep(j, 0, N-1) scanf("%d", &A[i][j]); int ans = INF; rep(i, 0, (1<<N)-1) ans = min(ans, query(i)); if(ans == INF) ans = -1; printf("%d\n", ans); return 0; }
- 1
信息
- ID
- 391
- 时间
- 1000ms
- 内存
- 125MiB
- 难度
- 5
- 标签
- 递交数
- 2
- 已通过
- 2
- 上传者