1 条题解
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0Guest
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1
# include <bits/stdc++.h> using namespace std; int a[45][45]; int main() { int N; cin >> N; int k = 1; int x = 1; int y = (N + 1) / 2; a[x][y] = k; k++; while (k <= N * N) { if (x == 1 && y != N) { x = N; y += 1; a[x][y] = k; k++; } else if (y == N && x != 1) { y = 1; x -= 1; a[x][y] = k; k++; } else if (x == 1 && y == N) { x += 1; a[x][y] = k; k++; } else { if (a[x - 1][y + 1] == 0) { x -= 1; y += 1; a[x][y] = k; k++; } else { x += 1; a[x][y] = k; k++; } } } for (int i = 1; i <= N; i++) { for (int j = 1; j <= N; j++) { printf("%d ", a[i][j]); } printf("\n"); } return 0; }
- 1
信息
- ID
- 464
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者