#P1907E. Good Triples

    ID: 9193 远端评测题 2000ms 256MiB 尝试: 1 已通过: 1 难度: 5 上传者: 标签>brute forcecombinatoricsnumber theory*1600

Good Triples

Description

Given a non-negative integer number $n$ ($n \ge 0$). Let's say a triple of non-negative integers $(a, b, c)$ is good if $a + b + c = n$, and $digsum(a) + digsum(b) + digsum(c) = digsum(n)$, where $digsum(x)$ is the sum of digits of number $x$.

For example, if $n = 26$, then the pair $(4, 12, 10)$ is good, because $4 + 12 + 10 = 26$, and $(4) + (1 + 2) + (1 + 0) = (2 + 6)$.

Your task is to find the number of good triples for the given number $n$. The order of the numbers in a triple matters. For example, the triples $(4, 12, 10)$ and $(10, 12, 4)$ are two different triples.

The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. Descriptions of test cases follow.

The first and only line of the test case contains one integer $n$ ($0 \le n \le 10^7$).

For each test case output one integer, the number of good triples for the given integer $n$. Order of integers in a triple matters.

Input

The first line of input contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases. Descriptions of test cases follow.

The first and only line of the test case contains one integer $n$ ($0 \le n \le 10^7$).

Output

For each test case output one integer, the number of good triples for the given integer $n$. Order of integers in a triple matters.

12
11
0
1
2
3
4
5
3141
999
2718
9999999
10000000
9
1
3
6
10
15
21
1350
166375
29160
1522435234375
3

Note

In the first example, the good triples are $(0, 0, 11)$, $(0, 1, 10)$, $(0, 10, 1)$, $(0, 11, 0)$, $(1, 0, 10)$, $(1, 10, 0)$, $(10, 0, 1)$, $(10, 1, 0)$, $(11, 0, 0)$.

In the second example, there is only one good triple $(0, 0, 0)$.