#P1503C. Travelling Salesman Problem

    ID: 248 远端评测题 2000ms 256MiB 尝试: 0 已通过: 0 难度: 8 上传者: 标签>binary searchdata structuresdpgreedyshortest pathssortingstwo pointers*2200

Travelling Salesman Problem

Description

There are $n$ cities numbered from $1$ to $n$, and city $i$ has beauty $a_i$.

A salesman wants to start at city $1$, visit every city exactly once, and return to city $1$.

For all $i\ne j$, a flight from city $i$ to city $j$ costs $\max(c_i,a_j-a_i)$ dollars, where $c_i$ is the price floor enforced by city $i$. Note that there is no absolute value. Find the minimum total cost for the salesman to complete his trip.

The first line contains a single integer $n$ ($2\le n\le 10^5$) — the number of cities.

The $i$-th of the next $n$ lines contains two integers $a_i$, $c_i$ ($0\le a_i,c_i\le 10^9$) — the beauty and price floor of the $i$-th city.

Output a single integer — the minimum total cost.

Input

The first line contains a single integer $n$ ($2\le n\le 10^5$) — the number of cities.

The $i$-th of the next $n$ lines contains two integers $a_i$, $c_i$ ($0\le a_i,c_i\le 10^9$) — the beauty and price floor of the $i$-th city.

Output

Output a single integer — the minimum total cost.

Samples

3
1 9
2 1
4 1
11
6
4 2
8 4
3 0
2 3
7 1
0 1
13

Note

In the first test case, we can travel in order $1\to 3\to 2\to 1$.

  • The flight $1\to 3$ costs $\max(c_1,a_3-a_1)=\max(9,4-1)=9$.
  • The flight $3\to 2$ costs $\max(c_3, a_2-a_3)=\max(1,2-4)=1$.
  • The flight $2\to 1$ costs $\max(c_2,a_1-a_2)=\max(1,1-2)=1$.

The total cost is $11$, and we cannot do better.