Score : $500$ points

Problem Statement

Snuke has read his own fortune for tomorrow, and learned that there are $N$ scenarios that can happen, one of which will happen tomorrow with equal probability. The $i$-th scenario will cost him $A_i$ yen (Japanese currency).

Following this, Snuke has decided to get insurance today. If he pays $x$ yen to his insurance company, he will get compensation of $\min(A_i,2x)$ yen when $A_i$ yen is lost. Here, he can choose any non-negative real number as $x$.

Snuke wants to minimize the expected value of the amount of money he loses, which is $x+A_i-\min(A_i,2x)$. Find the minimized value.

Constraints

• $1 \leq N \leq 10^5$
• $1 \leq A_i \leq 10^9$
• All values in input are integers.

Input

Input is given from Standard Input in the following format:

$N$

$A_1$ $A_2$ $\cdots$ $A_N$

Output

Print the answer. Your answer will be judged correct when its absolute or relative error is at most $10^{-6}$.

3
3 1 4

1.83333333333333333333

The optimum choice is $x=1.5$. After paying $1.5$ yen, one of the following three scenarios will happen with equal probability:

• Scenario $1$: Lose $3$ yen and get compensation of $\min(3,2x)=3$ yen. After all, Snuke loses $x+A_1-\min(A_1,2x)=1.5+3-3=1.5$ yen.
• Scenario $2$: Lose $1$ yen and get compensation of $\min(1,2x)=1$ yen. After all, Snuke loses $x+A_2-\min(A_2,2x)=1.5+1-1=1.5$ yen.
• Scenario $3$: Lose $4$ yen and get compensation of $\min(4,2x)=3$ yen. After all, Snuke loses $x+A_3-\min(A_3,2x)=1.5+4-3=2.5$ yen.

Thus, the expected amount of money lost is $(1.5+1.5+2.5)/3=1.833333\cdots$ yen.

10
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