#ABC239B. [ABC239B] Integer Division

[ABC239B] Integer Division

Score : 200200 points

Problem Statement

Given an integer XX between 1018-10^{18} and 101810^{18} (inclusive), print X10\left\lfloor \dfrac{X}{10} \right\rfloor.

Notes

For a real number xx, x\left\lfloor x \right\rfloor denotes "the maximum integer not exceeding xx". For example, we have $\left\lfloor 4.7 \right\rfloor = 4, \left\lfloor -2.4 \right\rfloor = -3$, and 5=5\left\lfloor 5 \right\rfloor = 5. (For more details, please refer to the description in the Sample Input and Output.)

Constraints

  • 1018X1018-10^{18} \leq X \leq 10^{18}
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

XX

Output

Print X10\left\lfloor \frac{X}{10} \right\rfloor. Note that it should be output as an integer.

47
4

The integers that do not exceed 4710=4.7\frac{47}{10} = 4.7 are all the negative integers, 0,1,2,30, 1, 2, 3, and 44. The maximum integer among them is 44, so we have 4710=4\left\lfloor \frac{47}{10} \right\rfloor = 4.

-24
-3

Since the maximum integer not exceeding 2410=2.4\frac{-24}{10} = -2.4 is 3-3, we have 2410=3\left\lfloor \frac{-24}{10} \right\rfloor = -3. Note that 2-2 does not satisfy the condition, as 2-2 exceeds 2.4-2.4.

50
5

The maximum integer that does not exceed 5010=5\frac{50}{10} = 5 is 55 itself. Thus, we have 5010=5\left\lfloor \frac{50}{10} \right\rfloor = 5.

-30
-3

Just like the previous example, 3010=3\left\lfloor \frac{-30}{10} \right\rfloor = -3.

987654321987654321
98765432198765432

The answer is 9876543219876543298765432198765432. Make sure that all the digits match.

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