#ABC233C. [ABC233C] Product

[ABC233C] Product

Score : 300300 points

Problem Statement

We have NN bags. Bag ii contains LiL_i balls. The jj-th ball (1jLi)(1\leq j\leq L_i) in Bag ii has a positive integer ai,ja_{i,j} written on it.

We will pick out one ball from each bag. How many ways are there to pick the balls so that the product of the numbers written on the picked balls is XX?

Here, we distinguish all balls, even with the same numbers written on them.

Constraints

  • N2N \geq 2
  • Li2L_i \geq 2
  • The product of the numbers of balls in the bags is at most 10510^5: i=1NLi105\displaystyle\prod_{i=1}^{N}L_i \leq 10^5.
  • 1ai,j1091 \leq a_{i,j} \leq 10^9
  • 1X10181 \leq X \leq 10^{18}
  • All values in input are integers.

Input

Input is given from Standard Input in the following format:

NN XX

L1L_1 a1,1a_{1,1} a1,2a_{1,2} \ldots a1,L1a_{1,L_1}

L2L_2 a2,1a_{2,1} a2,2a_{2,2} \ldots a2,L2a_{2,L_2}

\vdots

LNL_N aN,1a_{N,1} aN,2a_{N,2} \ldots aN,LNa_{N,L_N}

Output

Print the answer.

2 40
3 1 8 4
2 10 5
2

When choosing the 33-rd ball in Bag 11 and 11-st ball in Bag 22, we have a1,3×a2,1=4×10=40a_{1,3} \times a_{2,1} = 4 \times 10 = 40. When choosing the 22-nd ball in Bag 11 and 22-nd ball in Bag 22, we have a1,2×a2,2=8×5=40a_{1,2} \times a_{2,2} = 8 \times 5 = 40. There are no other ways to make the product 4040, so the answer is 22.

3 200
3 10 10 10
3 10 10 10
5 2 2 2 2 2
45

Note that we distinguish all balls, even with the same numbers written on them.

3 1000000000000000000
2 1000000000 1000000000
2 1000000000 1000000000
2 1000000000 1000000000
0

There may be no way to make the product XX.