Score: $400$ points

Problem Statement

Takahashi became a pastry chef and opened a shop La Confiserie d'ABC to celebrate AtCoder Beginner Contest 100.

The shop sells $N$ kinds of cakes. Each kind of cake has three parameters "beauty", "tastiness" and "popularity". The $i$-th kind of cake has the beauty of $x_i$, the tastiness of $y_i$ and the popularity of $z_i$. These values may be zero or negative.

Ringo has decided to have $M$ pieces of cakes here. He will choose the set of cakes as follows:

• Do not have two or more pieces of the same kind of cake.
• Under the condition above, choose the set of cakes to maximize (the absolute value of the total beauty) + (the absolute value of the total tastiness) + (the absolute value of the total popularity).

Find the maximum possible value of (the absolute value of the total beauty) + (the absolute value of the total tastiness) + (the absolute value of the total popularity) for the set of cakes that Ringo chooses.

Constraints

• $N$ is an integer between $1$ and $1 \ 000$ (inclusive).
• $M$ is an integer between $0$ and $N$ (inclusive).
• $x_i, y_i, z_i \ (1 \leq i \leq N)$ are integers between $-10 \ 000 \ 000 \ 000$ and $10 \ 000 \ 000 \ 000$ (inclusive).

Input

Input is given from Standard Input in the following format:

$N$ $M$

$x_1$ $y_1$ $z_1$

$x_2$ $y_2$ $z_2$

$:$ $:$

$x_N$ $y_N$ $z_N$

Output

Print the maximum possible value of (the absolute value of the total beauty) + (the absolute value of the total tastiness) + (the absolute value of the total popularity) for the set of cakes that Ringo chooses.

5 3
3 1 4
1 5 9
2 6 5
3 5 8
9 7 9

56

Consider having the $2$-nd, $4$-th and $5$-th kinds of cakes. The total beauty, tastiness and popularity will be as follows:

• Beauty: $1 + 3 + 9 = 13$
• Tastiness: $5 + 5 + 7 = 17$
• Popularity: $9 + 8 + 9 = 26$

The value (the absolute value of the total beauty) + (the absolute value of the total tastiness) + (the absolute value of the total popularity) here is $13 + 17 + 26 = 56$. This is the maximum value.

5 3
1 -2 3
-4 5 -6
7 -8 -9
-10 11 -12
13 -14 15

54

Consider having the $1$-st, $3$-rd and $5$-th kinds of cakes. The total beauty, tastiness and popularity will be as follows:

• Beauty: $1 + 7 + 13 = 21$
• Tastiness: $(-2) + (-8) + (-14) = -24$
• Popularity: $3 + (-9) + 15 = 9$

The value (the absolute value of the total beauty) + (the absolute value of the total tastiness) + (the absolute value of the total popularity) here is $21 + 24 + 9 = 54$. This is the maximum value.

10 5
10 -80 21
23 8 38
-94 28 11
-26 -2 18
-69 72 79
-26 -86 -54
-72 -50 59
21 65 -32
40 -94 87
-62 18 82

638

If we have the $3$-rd, $4$-th, $5$-th, $7$-th and $10$-th kinds of cakes, the total beauty, tastiness and popularity will be $-323$, $66$ and $249$, respectively. The value (the absolute value of the total beauty) + (the absolute value of the total tastiness) + (the absolute value of the total popularity) here is $323 + 66 + 249 = 638$. This is the maximum value.

3 2
2000000000 -9000000000 4000000000
7000000000 -5000000000 3000000000
6000000000 -1000000000 8000000000

30000000000

The values of the beauty, tastiness and popularity of the cakes and the value to be printed may not fit into 32-bit integers.