#P2903. [USACO08MAR] The Loathesome Hay Baler S

    ID: 698 远端评测题 1000ms 125MiB 尝试: 0 已通过: 0 难度: (无) 上传者: 标签>广度优先搜索BFS搜索模拟USACO2008

[USACO08MAR] The Loathesome Hay Baler S

题目描述

Farmer John has purchased the world's most loathesome hay baler. Instead of having a drive-roller that drives maybe an idler roller that drives the power take-off for the baler, it has N rollers (2 <= N <= 1050) which drive and are driven by various rollers.

FJ has meticulously cataloged data for each roller i: X_i,Y_i are the center of the roller (-5000 <= X_i <= 5000; -5000 <= Y_i <= 5000); R_i is the roller's radius (3 <= R_i <= 800). The drive-roller is located at 0,0; the baler power take-off is located at X_t,Y_t (numbers supplied in the input).

The drive-roller turns clockwise at 10,000 revolutions per hour. Your job is to determine the speeds of all the rollers that are in the power-train: from the drive-roller through the power take-off roller. Rollers that do not transfer power to the take-off roller are to be ignored. A roller of radius Rd that is turning at S rph and driving another roller of radius Rx will cause the second roller to turn at the speed -S*Rd/Rx (where the sign denotes whether the roller is turning clockwise or counterclockwise (anticlockwise for our British friends)).

Determine the power-train path and report the sum of the absolute values of all those rollers' speeds. All the rollers in the input set except the driver-roller are driven by some other roller; power is never transferred to a roller from more than one other roller.

Report your answer as an integer that is the truncated value after summing all the speeds.

Farmer John新买的干草打包机的内部结构大概算世界上最混乱的了,它不象普通的机器一样有明确的内部传动装置,而是,N (2 <= N <= 1050)个齿轮互相作用,每个齿轮都可能驱动着多个齿轮。 FJ记录了对于每个齿轮i,记录了它的3个参数:X_i,Y_i表示齿轮中心的位置坐标(-5000 <= X_i <= 5000; -5000 <= Y_i <= 5000);R_i表示该齿轮的半径(3 <= R_i <= 800)。

驱动齿轮的位置为0,0,并且FJ也知道最终的工作齿轮位于X_t,Y_t。 驱动齿轮顺时针转动,转速为10,000转/小时。你的任务是,确定传动序列中所有齿轮的转速。传动序列的定义为,能量由驱动齿轮传送到工作齿轮的过程中用到的所有齿轮的集合。对能量传送无意义的齿轮都应当被忽略。

在一个半径为Rd,转速为S转/每小时的齿轮的带动下,与它相接的半径为Rx的齿轮的转速将为-S*Rd/Rx转/小时。S前的负号的意思是,一个齿轮带动的另一个齿轮的转向会与它的转向相反。

FJ只对整个传动序列中所有齿轮速度的绝对值之和感兴趣,你的任务也就相应转化成求这个值。机器中除了驱动齿轮以外的所有齿轮都被另外某个齿轮带动,并且不会出现2个不同的齿轮带动同一个齿轮的情况。

输入格式

* Line 1: Three space-separated integers: N, X_t, and Y_t

* Lines 2..N+1: Line i+1 describes roller i's properties: X_i, Y_i, and R_i

输出格式

* Line 1: A single integer that is the truncated version of the sum of the absolute value of the speeds of the rollers in the power-train including the drive-roller, all the driven rollers, and the power take-off roller.

4 32 54 
0 0 10 
0 30 20 
32 54 20 
-40 30 20 
20000 

提示

Four rollers: the drive-roller at 0,0 with radius 10. It drives the roller above it at 0,30 with radius 20. That roller drives both the power take-off roller at 32,54 (r=20) and a random roller (not in the power train) at -40,30 (r=20).

Roller Radius Speed

1 (0,0) 10 10,000

2 (0,30) 20 -5,000

3 (32,54) 20 5,000


Sum of abs values: 20,000